`2x+9x+1x=180`

The angles of a triangle are in the ratio 2:3:4 . Find them The following are the steps involved in solving the above problem. Arrange them in sequential order from the first to the last. (A) 2x+3x+4x=180^(@) implies 9x= 180^(@)implies x=20^(@) (B) Let the angles be A,B and C. Given A:B:C=2:3:4 implies A=2x,B=3x=C=4x (C ) We know that the sumf of the angles of a triangle is 180^(@), ie., A+B+C=180^(@) (D) The angles are :A=2(20^(@))=40^(@),B=3(20^(@))= 60^(@) and C=4(20^(@))=80^(@) .

Solve x ^(5) - 5x ^(4) + 9x ^(3) - 9x ^(2) + 5x -1 =0.

The eccentricity of ellipse 4(x-2y+1)^2 +9(2x+y+2)^2=180 is

The eccentricity of ellipse 4(x-2y+1)^2 +9(2x+y+2)^2=180 is

Solve : (2x^2 - 3x+1) (2x^2 + 5x + 1) = 9x^2 .

Prove that: (x+1) and (2x-3) are factors of 2x^3-9x^2+x+12

Show that x+1 and 2x-3 are factors of 2x^3-9x^2+x+12

The equation of the normal at the point P (2, 3) on the ellipse 9x^(2) + 16y^(2) = 180 , is