A simple harmonic motion is represented by `F(t)=10sin(20t+0.5)`. The amplitude of the S.H.M. is

A simple harmonic motion is represented by x=10sin(20t+0.5). Write down its amplitude, angular frequency, frequency, time period and initial phase if displacement is measured in metres and time seconds.

A simple harmonic motion is represented by x=10sin (20t+0.5) where x is in metre and t is in second. Find its amplitude, angular frequency, frequency and time period.

A simple harmonic motion is represented by : y=5(sin3pit+sqrt(3)cos3pit)cm The amplitude and time period of the motion by :

A simple harmonic motion is represented as x = 20 sin (2pi)t + 0.5]m find amplitude, angular frequency time period and initial phase.

A simple harmonic motion is represented by x = 12 sin (10 t + 0.6) Find out the maximum acceleration, if displacement is measured in metres and time in seconds.

The equation of simple harmonic is as following y(t) = 10 sin (20t+ 45^(@)) . Find the amplitude of SHM.

A simple harmonic motion is represented by the equation, y = 5 sin pi(t+4) . Then the values of amplitude A and initial phase prop are respectively.

A simple harmonic motion is represented by the equation, y = 5 sin pi(t+4) . Then the values of amplitude A and initial phase prop are respectively.