A moving train is brought to rest within ` 20` seconds by applying brakes. Find the initial velocity , if the retardation due to brakes is `2 m//s^(2)`.

Find the initial velocity of a car which is stopped in 10 seconds by applying brakes. The retardation due to brakes is 2.5 m/ s^(2) .

A train moving with a velocity of 20 m s^(-1) ' is brought to rest by applying brakes in 5 s. Calculate the retardation.

A local train, travelling at 72 km/hr is brought to rest in 10 seconds by applying the brake. How much is the acceleration produced in this case? Also how much is distance (s) covered by the train before coming to rest?

A bus running at a speed of 18 km/h is stopped in 2.5 seconds by applying brakes. Calculate the retardation produced.

A train moving at 54 "km.h^(-1) is brought to rest in 1 min on application of brakes. What is the retardation of the train? Also find the distance travelled by the train after application of the brakes.

A car is moving in a straight line with speed 18 km h^(-1) . It is stopped in 5 s by applying the brakes. Find the retardation

A car of mass 2400 kg moving with a velocity of 20 m s^(-1) is stopped in 10 seconds on applying brakes Calculate the retardation and the retarding force.

A driver is driving a car at a speed of 90km/h. he spots a child standing on his way and decided to apply the brakes but it took him 0.3s to actually apply the brakes. If the retardation produced by the brakes is 10m//s^(2) , calcualtion the total distance covered by car before coming to rest

A moving train is stopped by applying brakes. It stops after travelling 80 m . If the speed of the train is doubled and retardation remain the same, it will cover a distance-

A moving train is stopped by applying brakes. It stops after travelling 80 m . If the speed of the train is doubled and retardation remain the same, it will cover a distance-