When 36.0 g of a solute having the empirical formula `CH_(2)O` is dissovled in 1.20 kg of water, the solution freezes at `-0.93^(@)C`. What is the moleculer formula of the solute ? (`K_(f) = 1.86^(@)C kg mol^(-1)`)

When 36g of a non-volatile, non-electrolytic solute having the empirical formula CH_(2)O is dissolved in 1.2 kg of water, the solution freezes at -0.93^(@)C . The molecular formula of the solute is ( K_(f) of water = 1.86 K kg mol^(-1) )

When 36.0g of a non -volatile, non-electrolyte solution an empirical formula CH_(2)O is dissolved inn 1.20Kg of water. The solution freezes at -0.93^(@)C . What is the no. of oxygen atoms present per molecule of solute? K_(f) of H_(2)O=1.86K kg mol^(-1) , Freezing point of H_(2)O=273K

A solution containing 1.8 g of a compound (empirical formula CH_(2)O ) in 40 g of water is observed to freeze at -0.465^(@) C. The molecules formulea of the compound is ( K_(f) of water =1.86kg K mol^(-1) ):

A solution containing 1.8 g of a compound (empirical formula CH_(2)O ) in 40 g of water is observed to freeze at -0.465^(@) C. The molecules formulea of the compound is ( K_(f) of water =1.86kg K mol^(-1) ):