A bus was moving with a speed of `54 km//h`. On applying brakes , it stopped in 8 seconds . Calculate the acceleration and the distance travelled before stopping.

(a) Derive the formula : v= u+at , where the symbols have usual meanings. (b) A bus was moving with a speed of 54 km/h. On applying brakes it stopped in 8 seconds. Calculate the acceleration.

A bus running at a speed of 18 km/h is stopped in 2.5 seconds by applying brakes. Calculate the retardation produced.

A car is moving with a velocity of 72km/h. By applying brakes a negative acceleration of 0.4m/s2 is produced. the distance covered by the car before it stops?

A car of mass 480 kg moving at a speed of 54 km per hour is stopped in 10 s. Calculate the force applied by the brakes.

A body of mass 10kg starting from rest, accelerates uniformly to a speed of 30m//s in 10s . Brakes are applied and the body stops in next 5 seconds , (figure). Calculate the accelerating force and the stopping force

A car has speed of 40km/h. on applying brakes it stops after 15m. If its speed was 80 km h^(-1) it would have stopped after

A car moving with a speed of 40 km/h can be stopped by applying brakes after at least 2m. If the same car is moving with a speed of 80 km/ h. The minimum stopping distance will be……………..

A car moving with a speed of 40 km/h can be stopped by applying brakes after at least 2 m. If the same car is moving with 80 km/h, what is the least stopping distance ?

A bus decreases its speed from 72 km//h to 54 km//h in 10 s . Calculate the acceleration of the bus.