The number of solutions (x, y, z) to the system of equations
`x+2y+4z=9,4yz+2xy=13,xyz=3`
Such that at least two of x, y, z are integers is -

The solution of the system of equations is x-y+2z=1,2y-3z=1 and 3x-2y+4y=2 is

The matrix form of the system of equations 2x-y+8z=13,3x+4y+5z=18 , 3x-2y-4z=-13 is

If the system of equations x+2y+3z=4,x+py+2z=3,x+4y+z=3 has an infinite number of solutions and solution triplet is

Statement - I The soluton of the system of equations 2x-y+3z=9,x+y+z=6,x-y+z=2 is x=1,y=2,z=3 Statement - II : The solution of the system of equations x+2y-z=3,3x=y+2z=1 , 2x-2y+3z=2 is x=-1,y=4,z=4 Which of the above Statement(s) is true ?

If the system of equations x + 2y + 3z = 4, x+ py+ 2z = 3, x+ 4y + z = 3 has an infinite number of solutions and solution triplet is

The system of equations {:(x+2y+3z=4),(2x+3y+4z=5),(3x+4y+5z=6):} has …………… solutions

Solve the following system of equations: x-y+z=4,\ \ \ \ x-2y-2z=9,\ \ \ \ 2x+y+3z=1