हल कीजिए `x cos^(2)ydx=ycos^(2)xdy`

xcos^(2)ydx-ycos^(2)xdy=0

Solve the following differential equations x cos^(2)ydx=ycos^(2)x dy

Solve the following differential equation: x cos^(2)ydx=y cos^(2)xdy

x cos^(2)ydx=ycos^(2)xdy A) xsin2y=ycos2x+c B) x tanx=ytany+c C) x tan x-y tan y=ln(secx/ sec y)+c D) x sec x=y sec y+c

xdy-ydx=xy^(2)dx

General solution of coty cos^(2)xdy+cotxcos^(2)ydx=0 is

Solve the following differential equations : tan x cdotcos^2ydx+tan ycdot cos^2xdy=0

The general solution of the differential equation x. cos(y/x)(ydx+xdy)=y sin(y/x)(xdy-ydx) is

The solution of cos((x)/(y))(ydx-xdy)=xy^(3)(xdy+ydx) is sin((x)/(y))=((xy)^(lambda))/(mu)+C then the value of (lambda+mu) is

x^(2)y(2xdy+3ydx)=dy