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102/125+5/18...

`102/125+5/18`

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Find out the average of 308, 125, 45, 120 and 102.

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Evaluate |[102, 18, 36],[ 1, 3, 4],[ 17, 3, 6]|

Find n such that (2/3)^3xx(2/3)^5=(2/3)^n^(-2) ((125)/8)^5xx((125)/8)^n=(5/2)^(18)

Find n such that (2/3)^3xx(2/3)^5=(2/3)^n^(-2) ((125)/8)^5xx((125)/8)^n=(5/2)^(18)

Find the 28th term from the end of the AP 6,9,12,15,18,…..,102

Write the value of the following determinant: |[102, 18, 36],[ 1, 3, 4],[17, 3, 6]|

Write the value of the following determinant: |[102, 18, 36],[ 1, 3, 4],[17, 3, 6]|

Write the value of the following determinant: |[102, 18, 36],[ 1, 3, 4],[17, 3, 6]|