Let `f (x) = {{:(2-|x ^(2) +5x +6|, x ne -2),( b ^(2)+1, x =-2):}`
Has relative maximum at `x =-2,` then complete set of values b can take is:

Let f(x)={(2-|x^2+5x+6|,x!=-2),(a^2+1,x=-2):} then value of 'a' so that f(x) has a maximum at x=-2 is

Let f (x) = {{:( x^(3) - x^(2) + 10 x- 5 , "," , x le 1), ( -2x + log _(2) (b^(2) - 2) , "," , x gt 1):} the set of values of b for which f(x) has greatest value at x = 1 is given by

Let f(x+(1)/(x) ) =x^2 +(1)/(x^2) , x ne 0, then f(x) =?

Let f(x) = {(x^(4)-5x^(2)+4)/(|(x-1)(x-2)|) x ne 1,2),(6, x=1), (12, x =2):} . Then, f(x) is continuous on the set

Let f(x) = 2x + 5. If x ne 0 then find (f (x +2) - f(2))/(x)

Let f(x+(1)/(x))=x^(2)+(1)/(x^(2)), x ne 0, then f(x)=

Let f(x) be defined as f(x)={tan^(-1)alpha-5x^2,0ltxlt1 and -6x ,xgeq1 if f(x) has a maximum at x=1, then find the values of alpha .

Let f(x) be defined as f(x)={tan^(-1)alpha-5x^2,0ltxlt1 and -6x ,xgeq1 if f(x) has a maximum at x=1, then find the values of alpha .