Solve `(i) 3x+17<=2(1-x), (ii) ((5x-2)/3)-((7x-3)/5)>x/4`

Solve: (17-3x)/5-(4x+2)/3=5-6x+(7x+14)/3

Solve: (17-3x)/5-(4x+2)/3=5-6x+(7x+14)/3

Solve: 4x+9=17 .

Solve |3x- 4x| lt 17 .

Solve: 2/3x+3/2x-3/4x=17/4

Solve : x+7-(8x)/(3)=(17x)/(6)-(5x)/(8)

Solve: (4x+17)/(18)-(13 x-2)/(17 x-32)+x/3=(7x)/(12)-(x+16)/(36)

Solve: (4x+17)/(18)-(13 x-2)/(17 x-32)+x/3=(7x)/(12)-(x+16)/(36)

If the replacement set is the set of natural numbers, solve : (i) x-5 lt 0 (ii) x+1 le 7 (iii) 3x-4 gt 6 (iv) 4x+1 ge 17