In Young's double slit experiment the distance of the screen from the plane of the slits is 1.0 m. The wavelength of light used and width of the fringe are 6000 Å and 2 mm respectively.
Distance between the slits is

In Young's double slit experiment the distance of the screen from the plane of the slits is 1.0 m. The wavelength of light used and width of the fringe are 6000 Å and 2 mm respectively. If the wavelength of the light used is 4800 Å, the width of the fringe will be

In Young's double slit experiment the distance between the two slits is d and wavelength of the light used is lambda . The angular width of the fringe

In Young's double slit experiment, the distance between the two slits is 0.1 mm and the wavelength of light used is 4 xx 10^(-7) m . If the width of the fringe on the screen is 4 mm , the distance between screen and slit is

In a double experiment, the distance between the slit is 1 mm and screen is 25 cm away from the slits. The wavelength of light is 6000Å . The width of the fringe on the screen is

In Young's double slit experiment angular width of a fringe formed on a distant screen is 0.1^(@) . The wavelength of the light used in the experiment is 6000 Å. What is the distance between the two slits ?

In young's double-slit experiment , the spacing between the slits is 'd' and the wavelength of light used is 6000Å If the angular width of a fringe formed on a distance screen is 1^@ then calculate 'd' .