If `S=sum_(n=1)^10 (2n + 1/2),` then `S`

If S=sum_(n=2)^oo (3n^2+1)/(n^2-1)^3 then 9/S=

If S_(n) = sum_(n=1)^(n) (2n + 1)/(n^(4) + 2n^(3) + n^(2)) then S_(10) is less then

If S_(n) = sum_(n=1)^(n) (2n + 1)/(n^(4) + 2n^(3) + n^(2)) then S_(10) is less then

Let S_1 = 4+6/3+8/3^2+10/3^3+...+oo and S_2 =sum_(n=1)^oo 1/((3n+1)(3n+4)), then the value of the S_1/(10 S_2) is

If S_(1)= sum_(r=1)^(n) r , S_(2) = sum_(r=1)^(n) r^(2),S_(3) = sum_(r=1)^(n)r^(3) then : lim_(n to oo ) (S_(1)(1+(S_(8))/8))/((S_(2))^(2)) =

Let S_(n)=sum_(r=1)^(oo)(1)/(n^(r)) and sum_(n=1)^(k)(n-1)S_(n)=5050, then k=

Given S_(n)=sum_(k=1)^(n)(k)/((2n-2k+1)(2n-k+1)) and T_(n)=sum_(k=1)^(n)(1)/(k) then (T_(n))/(S_(n)) is equal to

Evaluate S=sum_(n=0)^n(2^n)/((a^(2^n)+1) (where a>1) .

Evaluate S=sum_(n=0)^n(2^n)/((a^(2^n)+1) (where a>1) .

Evaluate S=sum_(n=0)^n(2^n)/((a^(2^n)+1) (where a>1) .