Let `omega!=1` be a complex cube root of unity. If `(4+5omega+6omega^2)^(n^2+2)+(6+5omega^2+4omega)^(n^2+2)+(5+6omega+4omega^2)^(n^2+2)=0,` then `n` can be- (1) 133 (2) 113 (3) 111 (4) 331

Let omega ne 1 be a complex cube root of unity. If ( 4 + 5 omega + 6 omega ^(2)) ^(n^(2) + 2) + ( 6 + 5omega^(2) + 4 omega ) ^(n ^(2) + 2) + ( 5+ 6 omega + 4 omega ^(2) ) ^( n ^(2) + 2 ) = 0 , and n in N , where n in [1, 100] , then number of values of n is _______.

If omega is a complex cube root of unity, then (1-omega+omega^(2))^(6)+(1-omega^(2)+omega)^(6)=

If omega is complex cube root of unity then (3+5 omega+3 omega^(2))^(2)+(3+3 omega+5 omega^(2))^(2) is equal to

If omega is complex cube root of unity then (3+5 omega+3 omega^(2))^(2)+(3+3 omega+5 omega^(2))^(2) is equal to

omega is a complex cube root of unity,then (1-omega)(1-+-ega^(2))(1-omega^(4))(1-omega^(8))

If omega is complex cube root of unity (1-omega+omega^(2))(1-omega^(2)+omega^(4))(1-omega^(4)+omega^(8))(1-omega^(8)+omega^(16))

If omega is a complex cube root of unity.Show that Det[[1,omega,omega^(2)omega,omega^(2),1omega^(2),1,omega]]=0

If omega is a complex cube root of unity then (1-omega+omega^(2))(1-omega^(2)+omega^(4))(1-omega^(4)+omega^(8))(1-omega^(8)+omega^(16))

Let omega ne 1 be a complex cube root of unity. If (3-3omega+2omega^(2))^(4n+3) + (2+3omega-3omega^(2))^(4n+3)+(-3+2omega+2omega^(2))^(4n+3)=0 , then the set of possible value(s) of n is are