If `A(4,-4)` and `B(9,6)` lies on `y^2=4x` and a point C on arc `AOB(O= origin)` such that the area of `triangleACB` is maximum then point c is (1) `(1/4,1)` (2) `(1,1/4)` (3) `(1,1/2)` (4) `(1/2,1)`

If A(4,-4) and B(9,6) lies on y^(2)=4x and a point C on arc AOB(O= or ig in) such that the area of /_ACB is maximum then point c is (1)((1)/(4),1) (2) (1,(1)/(4))(3)(1,(1)/(2)) (4) ((1)/(2),1)

Let A(4,-4) and B(9,6) be points on the parabola y^(2)=4x. Let C be chosen on the on the arc AOB of the parabola where O is the origin such that the area of DeltaACB is maximum. Then the area (in sq. units) of DeltaACB is :

Let A(4,-4) and B(9,6) be points on the parabola y^(2)=4x. Let C be chosen on the on the arc AOB of the parabola where O is the origin such that the area of DeltaACB is maximum. Then the area (in sq. units) of DeltaACB is :

Let A(4,-4) and B(9,6) be points on the parabola y^(2)=4x. Let C be chosen on the on the arc AOB of the parabola where O is the origin such that the area of DeltaACB is maximum. Then the area (in sq. units) of DeltaACB is :

Let A(4,-4) and B(9,6) be points on the parabola y^(2)=4x. Let C be chosen on the on the arc AOB of the parabola where O is the origin such that the area of DeltaACB is maximum. Then the area (in sq. units) of DeltaACB is :

The point on the curve y^2=x where tangent makes 45o angle with x-axis is (1//2,\ 1//4) (b) (1//4,\ 1//2) (c) (4,\ 2) (d) (1,\ 1)

The point on the curve y^2=x where tangent makes 45^o angle with x-axis is (a) (1//2,\ 1//4) (b) (1//4,\ 1//2) (c) (4,\ 2) (d) (1,\ 1)

The points A (4,5,1), B (0,-1,-1), C(3,9,4) and D(-4,4,4) are

Find the point on the parabola y=(x-3)^2, where the tangent is parallel to the line joining (3,0) and (4,1). a) (5/2,1/4) b) (5/2,3/4) c) (7/2,1/4) d) (1/2,1/4)

The line x+2y=1 cuts the ellipse x^(2)+4y^(2)=1 1 at two distinct points A and B. Point C is on the ellipse such that area of triangle ABC is maximum, then find point C.