The above 3 Figures (a) and (b) show refraction of a ray in air incident at `60^(@)` with the normal to a glass - air and water-air figures interface respectively. Predict the angle of refraction in glass when the angle of incidence in water is `45^(@)` with the normal to a water - glass interface [Fig. (c) ]

Explanation

`n_(ga)=1.51, u_(wa)=1.32, n_(gw)=1.144,` which gives `sinr=0.6181` i.e., `r~=38^(@)`