Home
Class 12
PHYSICS
A person with a normal near point (25 cm...

A person with a normal near point (25 cm) using a compound microscope with objective of focal length 8.0 mm and an eyepiece of focal length 2.5cm can bring an object placed at 9.0mm from the objective in sharp focus. What is the separation between the two lenses? Calculate the magnifying power of the microscope,

Text Solution

Verified by Experts

Angular magnification of the eye-piece for image at 25cm
`=(25)/(2.5)+1=11, |u_(e)|=(25)/(11)cm=2.27cm, v_(o)=7.2cm`
Separation = 9.47 cm, Magnifying power = 88
Promotional Banner

Similar Questions

Explore conceptually related problems

A compound microscope consists of an object lens of focal length 2 cm and an eyepiece of focal length 5 cm. When an object is placed at 2.2 cm from the object lens, the final image is at 25 cm from the eye lens. What is the distance between the lenses ? What is the total linear magnification ?

A small telescope has an objective lens of focal length 144 cm and an eyepiece of focal length 6.0 cm. What is the magnifying power of the telescope ? What is the separation between the objective and the eyepiece ?

A compound microscope has an objective of focal length 4 mm and an eye-piece of focal length 25 mm. The objective produces a real image at a distance of 180 mm. If the eye-piece is in normal adjustment the magnification is

In a compound microscope, the focal lengths of two lenses are 1.5 cm and 6.25 cm. An object is placed at 2 cm from the objective and the final image is formed at 25 cm from the eye lens. The distance between the two lenses is … (in cm).