If the equation `x^(2)+4+3sin(ax+b)-2x=0` has at least one real solution, where `a,b in [0,2pi]` then one possible value of `(a+b)` can be equal to

If the equation x^(2)+12+3sin(a+bx)+6x=0 has atleast one real solution, where a, b in [0,2pi] , then the value of a - 3b is (n in Z)

If the equation x^(2)+12+3sin(a+bx)+6x=0 has atleast one real solution, where a, b in [0,2pi] , then the value of a - 3b is (n in Z)

If the equation x^(2)+12+3sin(a+bx)+6x=0 has atleast one real solution, where a, b in [0,2pi] , then the value of a - 3b is (n in Z)

If the equation x^(2) + 12 + 3 sin (a + bx) + 6x = 0 has at least one real solution, when a, b in [0, 2 pi] , then the value of a = 3b is (n in Z)

The equation 3x^(2)+4ax+b=0 has atleast one root in (0, 1) if :

If a,b in [0,2pi] and the equation x^(2)+4+3sin(ax+b)-2x=0 has at least one solution, then the value of (a+b) can be

If a , b in [0,2pi] and the equation x^2+4+3sin(a x+b)-2x=0 has at least one solution, then the value of (a+b) can be

If a , b in [0,2pi] and the equation x^2+4+3sin(a x+b)-2x=0 has at least one solution, then the value of (a+b) can be

If 3sin x+4cos ax=7 has at least one solution,then find the possible values of a.

If a,b in[0,2 pi] and the equation x^(2)+4+3sin(ax+b)-2x=0 has at least one solution,then the value of (a+b) can be (a) (7 pi)/(2) (b) (5 pi)/(2) (c) (9 pi)/(2) (d) none of these