Given these reactions :
`Ato2B DeltaH=40KJ`
` BtoCDeltaH=-50KJ`
` 2CtoD DeltaH=-20KJ`
Calculate `DeltaH` for the reaction : `D+Ato4C`

Consider the following process :- Ato2B,DeltaH=+150 KJ 3Bto2C+D,DeltaH=+350 KJ G+Ato2D,DeltaH=+350 KJ For B+DtoG+2C,DeltaH will be

If (1)/(2)AtoB,DeltaH=+150kJ*mol^(-1),3B to 2C+D,DeltaH=-125kJ*mol^(-1),E+Ato2D,DeltaH=+350kJ*mol^(-1) then DeltaH of the reaction B+D to E+2C will be-

Given that C_((g))+O_(2(g)) to CO_(2(g)) DeltaH^@=-a kJ , 2 CO_((g)) + O_(2(g)) to 2CO_(2(g)) 'DeltaH^@ =-b kJ , Calculate the DeltaH^@ for the reaction C_((g)) +1//2O_(2(g)) to CO_((g))

The DeltaH values for reactions of , C(s) + 1/2 O_2 (g) to CO(g) DeltaH =-100 KJ CO(g) + 1/2 O_2 (g) to CO_2 (g) DeltaH = 200 KJ The heat of reaction for C(s) + O_2 (g) to CO_2 (g) is

For a reaction DeltaH=+29kJ" "mol^(-1),DeltaS=-35KJ^(-1)" "mol^(-1) at what temperature, the reaction will be spontaneous?