Starting from the origin a body osillates simple harmonicall with a period of 2 s. A fter what time will its kinetic energy be 75% of the total energy?

Starting from the origin, a body oscillates simple harmonically with a period of 2 s. After what time will its kinetic energy be 25% of the total energy?

Starting from the origin, a body oscillates simple harmonically with a period of 2s. After a certain time (t) its kinetic energy will be 75% of the total energy. What should be the value of 1/t("in "s^(-1)) ?

Starting from the origin a body oscillates simple harmonically with a period of 2s . After time (1)/(x) second willthe kinetic energy be 75% of its total energy , then value of x is

Starting from the origin a body oscillates simple harmonically with a period of 2s . After time (1)/(x) second willthe kinetic energy be 75% of its total energy , then value of x is

starting from the mean position a body oscillates simple harmonically with an amplitude of 2m and a period of 2s . after what time will its kinetic energy be 75% of the total energy?

Starting from the origin a body executes simple harmonic oscillation with the period 2s. The time after which its potential energy will be 25% of the total energy is :

A particle starting from mean position executes simple harmonic motion with a period 8s. The maximum time in which its potential energy becomes half of the total energy is