`("cosh x - 1")/("sinhx")` =

("cosh x + 1")/("cosh x -1") = "coth "^2x/k, "then k"=

Show that (cosh(2x)-1)/(sinh(2x)) = (sinh(2x))/(1+cosh(2x))=tanhx

("cosh x")/("1 -tanhx") + ("sinh x")/( "1 - coth x") =

("cosh x +sinh x")^n =

cosh ^ (- 1) (2) =

Evalute the following integrals int (1)/("cosh x+ sinh x ") dx

I : ("tanh x")/("sech x - 1") + ("tanh x ")/("sech x + 1") + " 2 cosech x = 0" "II :" ("cosh x")/("1 - tanh x") + ("sinh x")/("1 - coth x")="sinh x + cosh x "