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If A is a 2 xx 2 matrix such that |A| ne...

If A is a `2 xx 2` matrix such that `|A| ne 0 " and " |A| = 5, ` write the value of |4A|.

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To find the value of |4A| where A is a 2x2 matrix and |A| = 5, we can follow these steps: ### Step 1: Understand the determinant property For any scalar \( k \) and an \( n \times n \) matrix \( A \), the property of determinants states: \[ |kA| = k^n |A| \] where \( n \) is the order of the matrix. ### Step 2: Identify the values In this case: - The scalar \( k = 4 \) - The order of the matrix \( n = 2 \) (since A is a 2x2 matrix) - The determinant of A, \( |A| = 5 \) ### Step 3: Apply the determinant property Using the property: \[ |4A| = 4^2 |A| \] ### Step 4: Calculate \( 4^2 \) Now calculate \( 4^2 \): \[ 4^2 = 16 \] ### Step 5: Substitute the values Now substitute the value of \( |A| \): \[ |4A| = 16 \times |A| = 16 \times 5 \] ### Step 6: Perform the multiplication Now calculate \( 16 \times 5 \): \[ 16 \times 5 = 80 \] ### Conclusion Thus, the value of \( |4A| \) is: \[ |4A| = 80 \] ---

To find the value of |4A| where A is a 2x2 matrix and |A| = 5, we can follow these steps: ### Step 1: Understand the determinant property For any scalar \( k \) and an \( n \times n \) matrix \( A \), the property of determinants states: \[ |kA| = k^n |A| \] where \( n \) is the order of the matrix. ...
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