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Find (dy)/(dx), when: y=cosxcos2x cos3...

Find `(dy)/(dx)`, when:
`y=cosxcos2x cos3x`

Text Solution

Verified by Experts

The correct Answer is:
`-(cosx cos2x cos3x).[tanx+2 tan 2x+3 tan 3x]`
`logy=log cosx+logcos2x+log cos3x`
`rArr(1)/(y).(dy)/(dx)=(-sinx)/(cosx)-(2sin2x)/(cos2x)-(3sin3x)/(cos3x)`
`rArr(dy)/(dx)=y.{-tanx-2 tan2x-3 tan 3x}.`
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