For each of the folowing differential equations, find a particular solution satisfying the given condition:
`(dy)/(dx) =y tan x ," it being given that "y =1 " when " x =0.`

Answer

`y = sec x`

Explanation

`int (1)/(y)dy = int tanx dx rArr log |y|=log |sec x|+log|C_(1)|`
`therefore (y cosx) = pm C_(1) = C.`
When x = 0 and y = 1, we het C = 1. Hence, `y = sec x . `