Find the general solution of each of the following differential equations:
`y log y dx - x dy =0`

Answer

`x =C log y`

Explanation

`int (1)/(x)dx = int (1)/(ylogy)dy rArr int (1)/(x) dx = int (dt)/(t), " where " log y = t.`
`therefore log|x| = log|t| + log|C_(1)| rArr log|x|-log|log y|=log|C_(1)|`
`rArr log|(x)/(log y)|=logC_(1) rArr (x)/(log y) = pm C_(1)=C.`