If `alpha and beta ` are the solution of ` a cos theta + b sin theta = c`, then

If alpha and beta are the solutions of a cos theta+b sin theta=c , then prove that : cos (alpha- beta)= (2c^2- (a^2+b^2))/(a^2+b^2) .

If alpha, beta are the solutions of a cos 2theta + b sin 2theta = c , then tan alpha tan beta=

If alpha and beta are the solutions of a cos theta+b sin theta=c, then show that cos(alpha+beta)=(a^(2)-b^(2))/(a^(2)+b^(2))( ii) cos(alpha-beta)=(2c^(2)-(a^(2)+b^(2)))/(a^(2)+b^(2))

If alpha and beta are the solutions roots of a cos theta+b sin theta=c, then choose the correct option (A)sin alpha+sin beta=(2bc)/(a^(2)+b^(2))(B)sin alpha sin beta=(c^(2)-a^(2))/(a^(2)+b^(2))(C)sin alpha+sin beta=(a^(2)-b^(2))/(c^(2)+b^(2))(D)sin alpha sin beta=(a^(2)-b^(2))/(c^(2)+b^(2))(D)

If alpha and beta are the solutions of a cos theta+b sin theta=c, show that sin alpha+sin beta=(2bc)/(a^(2)+b^(2)) and sin alpha sin beta=(c^(2)-a^(2))/(a^(2)+b^(2))