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Show that (-sqrt(-1))^(4n+3) =i, where n...

Show that `(-sqrt(-1))^(4n+3) =i`, where n is a positive integer.

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To show that \((- \sqrt{-1})^{4n+3} = i\), where \(n\) is a positive integer, we can follow these steps: ### Step 1: Rewrite \(-\sqrt{-1}\) We know that \(\sqrt{-1} = i\). Therefore, we can rewrite \(-\sqrt{-1}\) as: \[ -\sqrt{-1} = -i \] ...
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