Fill in the blanks with correct inequality sign `(gt,lt,ge,le)`.
(i) `5xlt20rArrx......4`
(ii) `-3xgt9rArr x ……-3`
(iii) `4xgt -16 rArr x…..-4`
(iv) `-6x le -18 rArr x ……3`
(v) `xgt-3rArr -2x ……6`
(vi) `altb and c lt 0 rArr (a)/(c)......(b)/(c)`
(vii) `p-q=-3 rArr p......q`
(viii) `u-v=2rArr u ...... v`

Answer

`(i) lt (ii)lt(iii)gt(iv) ge(v)lt(vi) gt(vii) lt(viii) gt`

Explanation

`(ii) -3xgt9rArrxlt-3." "(iii)4xgt-16rArrxgt-4.`
`(iv) -6xle-18rArrxge3." "(v)xgt-3rArr-2xlt6`.
`(vi) a ltb and c lt0 rArr (a)/(c)gt(b)/(c)." " (vii)p-q=-3 rArr pltq`.