Home
Class 11
MATHS
The ratio of the sum of first three term...

The ratio of the sum of first three terms is to that of first 6 terms of a G.P. is 1:12. Find the common ratio.

Text Solution

Verified by Experts

The correct Answer is:
`3/5`
`(a(r^(3)-1))/((r-1))xx((r-1))/(a(r^(6)-1))=125/152 rArr 1/((r^(3)+1))=125/152 rArr (r^(3)+1)=152/125`.
`:. r^(3)=(152/125-1)=27/125=(3/5)^(3)rArr r=3/5`.
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL PROGRESSION

    RS AGGARWAL|Exercise EXERCISE 12G|13 Videos

  • FUNCTIONS

    RS AGGARWAL|Exercise EXERCISE 3F VERY-SHORT-ANSWER QUESTIONS|21 Videos

  • GRAPHS OF TRIGONOMETRIC FUNCTIONS

    RS AGGARWAL|Exercise EXERCISE 19|6 Videos

Similar Questions

Explore conceptually related problems

The ratio of the sum of first three terms to the sum of first six terms is 125 : 152. Find the common ratio of G.P.

If the sum of first 10 terms is 33 times the sum of first 5 terms of G.P. find the common ratio.

The ratio of sum of first three terms of G.P. to the sum of first six terms is 64:91 ,the common ratio of G.

If the ratio fo the sum of first three terms of a GP to the sum of first six terms is 448 : 455 , then find the common ratio.

The sum of first three terms of a G.P. is 21 and sum of their squares is 189. Find the common ratio :

The ratio of the sum of 3 terms to the sum of 6 terms of a G.P. is 125:152. Its common ratio is :

The sum of first 12 terms of a G.P. is five times the sum of the first 6 terms. Find the common ratio.

The sum of first 6 terms of a G.P. is nine times the sum of the first 3 terms. Find the common ratio.

The sum of the first four terms of a geometric series is 520. The sum of the first five terms is 844. The sum of the first six terms is 1330. (a) Find the common ratio of the geometric progression.(b) Find the sum of the first two terms.