Show that the lines 3x-4y+5=0,7x-8y+5=0 and 4x+5y=45 are concurrent. Also find their point of intersection.

Explanation

To show that the lines \(3x - 4y + 5 = 0\), \(7x - 8y + 5 = 0\), and \(4x + 5y = 45\) are concurrent, we will find the point of intersection of any two lines and check if this point lies on the third line.

### Step 1: Write down the equations of the lines
The three lines are:
1. \(3x - 4y + 5 = 0\) (Line 1)
2. \(7x - 8y + 5 = 0\) (Line 2)
3. \(4x + 5y = 45\) (Line 3)

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