Home
Class 11
MATHS
Find the equation of a circle, the end...

Find the equation of a circle, the end points of one of whose diameters are ` A (2, -3)` and `B(-3, 5)`.

Text Solution

AI Generated Solution

To find the equation of a circle given the endpoints of its diameter, we can follow these steps: ### Step 1: Find the center of the circle The center of the circle can be found by calculating the midpoint of the diameter endpoints \( A(2, -3) \) and \( B(-3, 5) \). The midpoint \( C \) is given by the formula: \[ C\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equation of the circle,the coordinates of the end points of one ofwhose diameters are (i)A(3,2) and B(2,5)

Find the equation of the circle, the end points of whose diameter are (2, -3) and (-2, 4) . Find its centre and radius.

Find the equation of the circle, the coordinates of the end points of one of whose diameters are (i) A (3, 2 ) and B(2, 5) (ii) A (5, - 3) and B(2, - 4 ) (iii) A(-2, -3) and B(-3, 5) (iv) A(p, q), B (r, s )

Fill up in each of the following (c) the equation of circle whose end point of of one of its diameter are (-2, 3) and (0,-1) is

Find the equation of the circle when the end points of a diameter of the circle are : (-2, -3) and (-3, 5)

Find the equation of the circle,the coordinates of the end points of whose diameter are (-1,2) and (4,-3) .

Find the equation of the circle when the end points of a diameter of the circle are : (-2, 3) and (3, -5)

Find the equation of the circle when the end points of a diameter of the circle are : (2, 3) and (-1, -3)

Find the equations of the circles the end points of whose diameter are as follows : (i) (0,6) and (6,0) (ii) (-1,3) and (2,4) (iii) (A+b,a-b) and (a-b,a+b) (iv) (0,0) and (2,2)

Find the equation of circle whose end points of diameters are given by (2,-1) and (3,4).