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Find the mean, variance and standard dev...

Find the mean, variance and standard deviation for the numbers 4, 6, 10, 12, 7, 8, 13, 12.

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To find the mean, variance, and standard deviation for the numbers 4, 6, 10, 12, 7, 8, 13, and 12, we will follow these steps: ### Step 1: Calculate the Mean The mean (average) is calculated using the formula: \[ \text{Mean} ( \bar{x} ) = \frac{\text{Sum of observations}}{\text{Number of observations}} \] First, we need to find the sum of the observations: \[ 4 + 6 + 10 + 12 + 7 + 8 + 13 + 12 = 72 \] Next, we count the number of observations: \[ \text{Number of observations} = 8 \] Now we can calculate the mean: \[ \bar{x} = \frac{72}{8} = 9 \] ### Step 2: Calculate the Variance Variance is calculated using the formula: \[ \text{Variance} ( \sigma^2 ) = \frac{\sum (x_i - \bar{x})^2}{n} \] Where \( x_i \) represents each observation, \( \bar{x} \) is the mean, and \( n \) is the number of observations. We will calculate \( (x_i - \bar{x})^2 \) for each observation: 1. \( (4 - 9)^2 = (-5)^2 = 25 \) 2. \( (6 - 9)^2 = (-3)^2 = 9 \) 3. \( (10 - 9)^2 = (1)^2 = 1 \) 4. \( (12 - 9)^2 = (3)^2 = 9 \) 5. \( (7 - 9)^2 = (-2)^2 = 4 \) 6. \( (8 - 9)^2 = (-1)^2 = 1 \) 7. \( (13 - 9)^2 = (4)^2 = 16 \) 8. \( (12 - 9)^2 = (3)^2 = 9 \) Now, we sum these squared differences: \[ 25 + 9 + 1 + 9 + 4 + 1 + 16 + 9 = 74 \] Now we can calculate the variance: \[ \sigma^2 = \frac{74}{8} = 9.25 \] ### Step 3: Calculate the Standard Deviation The standard deviation is the square root of the variance: \[ \sigma = \sqrt{\sigma^2} = \sqrt{9.25} \approx 3.04 \] ### Final Results - Mean: \( 9 \) - Variance: \( 9.25 \) - Standard Deviation: \( 3.04 \)
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