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Given : 15 cotA = 8 find sinA and secA...

Given : `15 cotA = 8 ` find `sinA and secA`

Text Solution

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The correct Answer is:
`sin A = (15)/(17), sec A=(17)/(8)`
` cot A=(8)/(15)implies tan A=(15)/(8) =(BC)/(AB).`
` therefore AC^(2)=AB^(2)+BC^(2)=(8)^(2)+(15)^(2)=64+225=289`
`implies AC=sqrt(289)=17.`
`therefore sin A=(BC)/(AC)=(15)/(17) and secA=(AC)/(AB)=(17)=(8).`
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