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If sintheta=a/b , find sectheta+tantheta...

If `sintheta=a/b` , find `sectheta+tantheta` in terms of `a` and `b` .

Text Solution

Verified by Experts

`sin theta =(a)/(b)=(BC)/(AC).`
`therefore AB^(2)=AC^(2)-BC^(2)=b^(2)-a^(2)`
`implies AB= sqrt(b^(2) -a^(2))=((b+a))/(sqrt((b-a)).sqrt((b+a)))`
`=(sqrt(b+a).sqrt(b+a))/(sqrt((b-a)).sqrt((b+a)))=sqrt((b+a)/(b-a)).`
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