If `3 cot theta= 2` , show that `((4 sin theta - 3 cos theta ))/((2 sin theta + 6 cos theta))=(1)/(3)`

Explanation

To solve the problem, we start with the equation given:

**Given:**
\[ 3 \cot \theta = 2 \]

We need to show that:
\[ \frac{4 \sin \theta - 3 \cos \theta}{2 \sin \theta + 6 \cos \theta} = \frac{1}{3} \]

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