If ax+b=0, then x=………

If alpha, beta are roots of the equation x^(2) + ax + b = 0 , then maximum value of - x^(2) + ax + b + (1)/(4) (alpha - beta )^(2) is

If f(x) {:(=x^(2)+ax+b", if "0 le x lt 2 ),(= 3x+2", if " 2 le x le 4 ),(=2ax + 5b ", if " 4 lt x le 8 ) :} is continuous on [ 0,8] then a-b = ……

If a and b ( != 0) are roots of x^(2) +ax + b = 0 , then the least value of x^(2) +ax + b ( x in R) is :

If x^(2)+ax+b=0 and x^(2)+bx+a=0,(a ne b) have a common root, then a+b is equal to

If x^(2)+ax+b=0 and x^(2)+bx+a=0,(a ne b) have a common root, then a+b is equal to

If one root is common is equations x^(2)-ax+b=0 and x^(2 ) +bx-a=0 , then :

If one root is common is equations x^(2)-ax+b=0 and x^(2 ) +bx-a=0 , then :

If x^(2)+ax+b=0 and x^(2)+bx+ca=0(a!=b) have a common root,then prove that their other roots satisfy the equation x^(2)+cx+ab=0

f(x)={(x^2+2x, "" xle0,),(ax+b, "" x >0,):} is continuous and differentiable at x =0, find the values of a and b

If x^2-ax+b=0 and x^2-px+q=0 have a root in common then the second equation has equal roots show that b+q=(ap)/2