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For any three vectors overset(to)(a),...

For any three vectors `overset(to)(a), overset(to)(b) " and " overset(to)(C )`
` (overset(to)(a) - overset(to)(b)). {(overset(to)(b)-overset(to)(c))xx(overset(to)(c)-overset(to)(a))} = 2overset(to)(a).(overset(to)(b)xx overset(to)(c))`

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The correct Answer is:
1
`(vec(a)-vec(b)).{(vec(b)-vec(c ))xx (vec(c )-vec(a)) }=(vec(a)-vec(b)).(vec(b)xx vec(c )-vec(b) xx vec(a) +vec(c )xx vec(a))`
`=vec(a) ". "(vec(b) xx vec(c )) -vec(b) .(vec(c )xx vec(a)) = [vec(a)vec(b)vec(c )]+[vec(a)vec(b)vec(c )]`
`=2 [vec(a)vec(b)vec(c )]=2vec(a).(vec(b)xx vec(c ))`
Hence it is a true statement .
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