Determine the impedance of a series LCR - circuit if the reactance of C and L are `250 Omega` and `220 Omega` respectively and R is `40 Omega`

Determine the impedance of a series LCR circuit, if the reactance of C and L are 250 Ohm and 220 Ohm respectively and R is 40 Ohm.

Impedance of a series LR circuit is 25 Omega . If the resistance is 20 Omega . Find the reactance.

A circuit contains R, L and C connected in series with an A. C. source. The values of the reactances for inductor and capacitor are 200Omega and 600Omega respectively and the impedance of the circuit is Z1 . What happens to the impedance of the same circuit if the values of the reactances are interchanged:-

An L.C.R series circuit consist of R=25Omega and the reactances of C and L is 12 Omega and 24 Omega respectively. The impedance of the circuit is

If the impedance of an L-C R circuit is 40 Omega , then the admitance of the circuit will be

In a series LCR circuit, the total reactance is 4 Omega and resistance is 3 Omega . Its power factor is

In a series LCR circuit, the total reactance is 4 Omega and resistance is 3 Omega . Its power factor is

Find capacitance in a series LCR circuit in order to get maximum power. ( X_L = 250 Omega and f = 50 Hz )

The resonant frequency of a series LCR circuit with L=2.0 H,C =32 muF and R=10 Omega is