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The equation to the circle whose radius ...

The equation to the circle whose radius is 3 and which touches internally the circle `x^(2)+y^(2)-4x+6y-12=0" at this point (-1,1) is"`

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Centre of the circle whose radius is 3 and which touches internally the circle x^(2)+y^(2)-4x-6y-12=0 at the point (-1 -1) is

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