`x^2+y-xy-x`

Factorize: x^(2)+y-x-xy

Let's simplify:- (x + y) (x^2 -xy + y^2) + ( x - y) (x^2 + xy + y^2)

Factorise: x ^(2) - xy + y -x

If x:y::5:2, then (x ^(2) - xy + y ^(2))/( x ^(2) + xy + y ^(2)) = ?

Show that the equation 2x^(2) + xy - y^(2) + x + 4y - 3 = 0 represents a pair of lines.

Factorize x^(2)y+2xy-3x-6

Find the equation of the two straight lines which together with those given by the equation 6x^2-xy-y^2+x+12y-35=0 will make a parallelogram whose diagnols intersect in the origin. a). 6x^2-xy-y^2-x-12y-35=0 b). 6x^2-xy-y^2-x-12y+35=0 c). 6x^2-xy-y^2-x+12y-35=0 d). 6x^2-xy-y^2+x-12y-35=0