Home
Class 11
CHEMISTRY
CsCl has cubic structure of ions in whic...

CsCl has cubic structure of ions in which `Cs^(+)` ion is present in the body -centre of the cube. If density is 3.99 g `cm^(-3)` :
(a) Calculate the length of the edge of a unit cell.
(b) What is the distance between `Cs^(+)` and `Cl^(-)` ions ?
(c) What is the radius of `Cs^(+)` ion if the radius of `Cl^(-)` ion is 180 pm ?

Promotional Banner

Similar Questions

Explore conceptually related problems

The CsCl has cubic sturcute of Cl^- ions in which Cs^+ ion is present in the body centre of the cube. Its density is 3.99 g cm^-3 . Calculate the length of the edge of unit cell.

The CsCl has cubic structure of Cl^(-) ions in which Cs^(+) in which Cs^(+) ion is present in the body centre of the cube. It density is 3.99g cm^(-3) . Then length of the edge of unit cell is :

The CsCl has cubic structure of Cl^(-) ions in which Cs^(+) in which Cs^(+) ion is present in the body centre of the cube. It density is 3.99g cm^(-3) . The radius of Cs^(+) ion if the radius of Cl^(-) ion is 180 p m is :

The distance between Na^(+) and Cl^(-) ion ion NaCI is 281 pm. What is the edge length of the cube

CsBr has BCC structure. The length of its side is 4.3 Å . The minimum distance between Cs^(+) and Br^(-) ion will be

The density of NH_(4)Cl is 1.534 g cm^(-3) . It crystallizes in the CsCl lattice. a. Calculate the length of the length of the edge of NH_(4)Cl unit cell. b. Calculate the shortest distance between a NH_(4)^(o+) ion and a Cl^(ɵ) ion. c. Calculate the radius of NH_(4)^(o+) ion if the radius of the Cl^(ɵ) ion is 181 pm

The density of NH_(4)Cl is 1.534 g cm^(-3) . It crystallizes in the CsCl lattice. a. Calculate the length of the length of the edge of NH_(4)Cl unit cell. b. Calculate the shortest distance between a NH_(4)^(o+) ion and a Cl^(ɵ) ion. c. Calculate the radius of NH_(4)^(o+) ion if the radius of the Cl^(ɵ) ion is 181 pm