`5(i)^(11) + 6(i)^(7) -9(i)^(9)` को सरल कीजिए।

Show that ((19- 7i)/(9 + i))^(12) + ((20 - 5i)/(7 - 6i))^(12) is real.

(i) (5^(2))^(7) = (ii) (7^(3)) (9^(3)) =

Simplify and write each of the following in exponential form: (i) 9^(11)-:9^7 (ii) (-7)^(13)-:(-7)^9 (iii) ((-3)/4)^7-:((-3)/4)^5

Find the value of : ( i ) 2^(6) (ii) 9^(3) (iii) 11^(2) (iv) 5^(4)

Write the following in the form x+iy: (i) i+i^(2)+i^(3)+i^(4) (ii) i^(4)+i^(8)+i^(12)+i^(16) (iii) i+i^(5)+i^(9)+i^(13) (iv) i^(9)+i^(10)+i^(11)+i^(12) .

(i) 5/9+7/9

Multiply: (i) ((-5)/9) by 4 (ii) ((-36)/7) by (-(28)/9)

Find the additive inverse of : (i) (5)/(9) " " (ii) (-15)/(8)" " (iii) (9)/(-11)" " (iv) (-6)/(-7)

If sum_(i=1)^(9) (x_(i)-5)=9 " and" sum_(i=1)^(9) (x_(i)-5)^(2)=45 , then the standard deviation of the 9 items x_(1),x_(2),..,x_(9) is

If sum _(i=1) ^(9) (x _(i) - 5) = 9 and sum_(i =1) ^(9) (x _(i) - 5) ^(2) = 45, then the standard deviation of the 9 terms x _(1), x _(2),....,x _(9) is