[" gth of the latus rectum of the parabola: "],[xquad " (ii) "3y^(2)=8x]

The latus rectum of the parabola y^2=-8x is 2.

Find the coordinates of the focus and the vertex, the equations of the directrix and the axis, and length of the latus rectum of the parabola: (i) y^(2)=12x (ii) y^(2)=10x (iii) 3y^(2)=8x

Find the coordinates of the focus and the vertex, the equations of the directrix and the axis, and length of the latus rectum of the parabola: (i) y^(2)=-8x (ii) y^(2)=-6x (iii) 5y^(2)=-16x

Write the focus, directrix, and length of latus rectum of the parabola: (ii) 5y ^2 = - 8x

The length of the latus rectum of the parabola is 3 y^(2)+6 y+8 x-5=0 is

The point of intersection of the two tangents at the ends of the latus rectum of the parabola (y+3)^(2)=8(x-2)

Find the length of the latus rectum of the parabola x^(2) = -8y .

Find the length of the latus rectum of the parabola x^(2) = -8y .

Find the length of the latus rectum of the parabola x^2=-8y