` p to q` is logically equivalent to

~ p ^^ q is logically equivalent to

~ p ^^ q is logically equivalent to

p rarr q is logically equivalent to

p harr q is logically equivalent to

STATEMENT-1 : (p rArr q) hArr (~q rArr~p) and STATEMENT-2 : p rArr q is logically equivalent to ~q rArr ~p

STATEMENT-1 : (p rArr q) hArr (~q rArr~p) and STATEMENT-2 : p rArr q is logically equivalent to ~q rArr ~p

Using truth table show that - (p vv q) vv (~ p ^^ q ) is logically equivalent to ~ p.

The incorrect statement is (a) p vec -q is logically equivalent to ~ pvvqdot (b) If the truth-values of p ,q, r are T , F , T respectively, then the truth value of (pvvq)^^(qvvr) is Tdot (c) ~(pvvqvvr)-= ~p^^~ q^^ ~r (d) The truth value of p^^~(p^^q) is always Tdot