[1.6,+2.9+3.12+....+n(3n+3)],[,=n(n+1)(n+2)]

By the Principle of Mathematical Induction, prove the following for all n in N : 3.6+6.9+9.12+......+ 3n(3n+3) = 3n(n + 1) (n + 2) .

3.6+6.9+9.12+....+3n(3n+3)=

3.6+6.9+9.12+....+3n(3n+3)=

By method of induction, prove that 1.6 + 2.9 + 3.12 +... +to n terms = n(n +1 )(n+2) for all n in N .

Prove that by using the principle of mathematical induction for all n in N : 1.2+ 2.3+ 3.4+ .....+n(n+1)= [(n(n+1)(n+2))/(3)]

Prove that by using the principle of mathematical induction for all n in N : 1.2+ 2.3+ 3.4+ .....+n(n+1)= [(n(n+1)(n+2))/(3)]

Prove the following by using the principle of mathematical induction for all n in N :- 1.2 + 2.3 + 3.4 +... +n.(n+1)=[(n(n+1)(n+2))/3]

Prove the following by the method of induction for all n in N : 1.2 + 2.3 + 3.4 +...+ n(n + 1) = n/3 (n+1)(n+2).

Prove the following by using the principle of mathematical induction for all n in N 3 xx 6 + 6 xx 9 + 9 xx 12 + …..+ (3n)(3n+3) = 3n(n+1)(n+2)