" 1."4x^(2)+20xy+25y^(2)

{:( "Column" A ,, "Column" B) , ("If" a^(2) - b^(2) = 16 "and" a- b = 2 "," "then" a + b,, "(a)" 3x^(2) - x - 11), ("The degree of " (x-a) (x-b) (x - c) (x-d) ,, "(b)" 3x^(2) - x + 5), (4x^(2) + 20xy + 25y^(2) ,, (c) 8), ((5x^(2) + 7x -3)- (2x^(2) + 8x -8) ,, (d) 4), (,, (e) (4x + 5y) (x+ 5y)), (,,(f) (2x + 5y)^(2)):}

3x^(2)-20xy-7y^(2)

Distance between the parallel lines 4x^(2)+20xy+25y^(2)+2x+5y-12=0

Factorise : 9x^(2) - 30xy + 25y^(2)

Find the products: (4x-5y)(16x^(2)+20xy+25y^(2))

The pair of lines 2x^(2)+3xy+5y^(2)=0 and 4x^(2)+21xy+25y^(2)=0 are

Let P_(1),p_(2),p_(3) be the perpendicular distance between pair of parallel lines represented by x^(2)-3x-4=0, y^(2)-5y+6=0,4x^(2)+20xy+25y^(2)=0 respectively then :

If equation 4x^(2)+2pxy+25y^(2)+2x+5y-1=0 represents parallel lines, then p is equal to

If equation 4x^(2)+2pxy+25y^(2)+2x+5y-1=0 represents parallel lines, then p is equal to