Home
Class 12
CHEMISTRY
Vapour pressure of water is 360 mm Hg, h...

Vapour pressure of water is 360 mm Hg, how much urea should be added to 200 mL water to reduce its vapour pressure by 0.5% (Molecular wt. of urea =60)`(100)/(3)g)`

Promotional Banner

Similar Questions

Explore conceptually related problems

Vapour pressure of water is 360 mm Hg. How much urea should be added to 200 mL water to reduce its vapour pressure by 0.05%?Molecular wt. of urea=60

The weight of urea to be dissolved in 100 g. of water to decrease the vapour pressure of water by 5% is

3 gms of urea is added to 36 gms of boiling water. How much lowering in its vapour pressures is noticed

What mass of urea be dissolved in 171 g of water so as to decrease the vapour pressure of water by 5% ?

What mass of urea be dissolved in 171 g of water so as to decrease the vapour pressure of water by 5% ?

What mass of urea be dissolved in 171 g of water so as to decrease the vapour pressure of water by 5% ?

The vapour pressure of water at room temperature is 30 mm of Hg. If the mole fraction of the water is 0.9, the vapour pressure of the solution will be :

Vapour pressure of pure water at 298 k is 23.8 mm Hg. Calculate the lowering of vapour pressure caused by adding 5g of sucrose in 50 g of water.

Vapour pressure of pure water at 298 k is 23.8 mm Hg. Calculate the lowering of vapour pressure caused by adding 5g of sucrose in 50 g of water.