x^(3)+x^(2)y+xy^(2)+y^(3)=81

If |x|<1 and |y|<1, find the sum of infinity of the following series: (x+y)+(x^(2)+xy+y^(2))+(x^(3)+x^(2)y+xy^(2)+y^(3))+

The factors of x^(3)-x^(2)y-xy^(2)+y^(3) are (a (x+y)(x^(2)-xy+y^(2))(b)(x+y)(x^(2)+xy+y^(2))(c)(x+y)^(2)(x-y)(d)(x-y)^(2)(x+y)

Add : x^(3) - x^(2)y + 5xy^(2) + y^(3) , -x^(3) - 9xy^(2) + y^(3), 3x^(2)y + 9xy^(2)

Find dy/dx in the following: x^3 +x^2y + xy^2 + y^3 = 81

Find (dy)/(dx) if x^3 + x^2y + xy^2 + y^3 = 81

If x^(3)+y^(3)+xy^(2)+x^(2)y-x^(2)-y^(2)=0 then int ydx=

Perform the division: (x ^(3) y ^(3) + x ^(2) y ^(3) - xy ^(4) + xy)div xy

x^(3) + xy^(2) - x^(2) y - y^(3) = "_______"

x^(3)-3xy^(2)=183x^(2)y-y^(3)=26 If x,y in N