[4x+2y+8=0-(1)],[2x+2y+2=0-11]

Solve for x and y: 2x + 3y + 1 = 0, 3x + 2y - 11 = 0

Let P be the point (1,0) and Q be a point on the locus y^(2)=8x. The locus of the midpoint of PQ is y^(2)+4x+2=0y^(2)-4x+2=0x^(2)-4y+2=0x^(2)+4y+2=0

The equation of the circle which cuts orthogonally the three circles x^(2) + y^(2) + 4x + 2y + 1 = 0 , 2x^(2) + 2y^(2) + 8x + 6y - 3 = 0 , x^(2) + y^(2) + 6x - 2y - 3 = 0 is

If A = [(1,2,0),(-2,-1,-2),(0,-1,1)] , find A^-1 using A^-1 solve the equations. X-2y = 10, 2x - y - z = 8, -2 y + z = 7

For the ellipse 4x ^(2)+ y ^(2) - 8x + 2y + 1=0, the focus and the equation of the directrix are respectively

The tangent to the circle x^(2)+y^(2)-4x+2y+k=0 at (1,1) is x-2y+1=0 then k=

The tangents to the circle x^(2)+y^(2)-4x+2y+k=0 at (1,1) is x-2y+1=0 then k=

The tangent to the circle x^(2)+y^(2)-4x+2y+k=0 at (1,1) is x-2y+1=0 then k=

If the circle x^(2) + y^(2) + 8x - 4y + c = 0 touches the circle x^(2) + y^(2) + 2x + 4y - 11 = 0 externally and cuts the circle x^(2) + y^(2) - 6x + 8y + k = 0 orthogonally then k =