f(x)=(1)/(2-sin3x)

Find the range of the following function given by f(x)=(1)/(2-sin 3x)

The range of the function f(x) = (1)/(2-sin 3x) is

The range of the function f(x) = (1)/(2-sin 3x) is

Find the range and domain of the function defined by f(x)= (1)/(2- sin 3x)

Find domain(i) f(x) = (1)/(x - 5) (ii) f(x) = (3 - x)/(x - 3) (iii) f(x) = (x^(2) - 1)/(x - 1) (iv) f(x) = (| x - 3 |)/(x - 3) (v) f(x) = (1)/(2 - sin 3x)

If f(x)={[(1-sin^2x)/(3cos^2x),xltpi/(2)],[a,x=pi/2],[(b(1-sinx))/((pi-2x)^2),x gtpi/2]} then f(x) is continuous at x=pi/2 ,if (a) a=1/3,b=2 (b) a=1/3,=8/3 (c) a=2/3,b=8/3 (d) none of these

If f(x)={((sin3x)/(e^(2x)-1),,,x!=0),(k-2,:,x=0):} is Continuous at x=0, then k=

If f(x)=(1-sin^(2)x)/(1+sin^(2)x)," then "3f'((pi)/(4))-f((pi)/(4))=

Find the domain of the function f(x)=sin^(-1)(2x-3)