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Figure 6-28 shows a 6.0 kg block on a 60...

Figure 6-28 shows a 6.0 kg block on a `60^(@)` ramp with a coefficient of static friction of 0.60. A force `vecF` is applied up the ramp. What magnitude of that force puts the block on the verge of sliding down the ramp? 6.0 kg

Answer

Step by step text solution for Figure 6-28 shows a 6.0 kg block on a 60^(@) ramp with a coefficient of static friction of 0.60. A force vecF is applied up the ramp. What magnitude of that force puts the block on the verge of sliding down the ramp? 6.0 kg by PHYSICS experts to help you in doubts & scoring excellent marks in Class 12 exams.

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Knowledge Check

  • A block of mass 2kg is kept on the floor. The coefficient of static friction is 0.4 . If a force F of 2.5N is applied on the block as shown in the figure, the frictional force between the block and the floor will be.

    A
    `2.5N`
    B
    `5N`
    C
    `7.84N`
    D
    `10N`

  • A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 3 N is applied on the block as shown in figure. The force of friction between the block and the floor is (Take g=10 m s^(-2) )

    A
    3 N
    B
    8 N
    C
    4 N
    D
    6 N

  • A block of mass 4 kg is kept on a rough horizontal surface. The coefficient of static friction is 0.8. If a force of 19 N is applied on the block parallel to the floor, then the force of friction between the block and floor is

    A
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    B
    18 N
    C
    19 N
    D
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    In Fig. 6-37, a block of mass m = 5.0 kg is at rest on a ramp. The coefficient of static friction between the block and ramp is not known. Find the magnitude of the net force exerted by the ramp on the block.

    A block of mass 2kg is at rest on a floor. The coefficient of static friction between block and the floor is 0.54. A horizontal force of 2.8N is applied to the block. What should be the frictional force between the block and the floor.

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    A block of mass M is sliding down the plane. Coefficient of static friction is mu_(s) and kinetic friction is mu_(k) . Then friction force acting on the block is :

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