Figure 6-28 shows a 6.0 kg block on a `60^(@)` ramp with a coefficient of static friction of 0.60. A force `vecF` is applied up the ramp. What magnitude of that force puts the block on the verge of sliding down the ramp? 6.0 kg

In Fig. 6-34 a block of weight W experiences two applied forces, each of magnitude W/2. What coefficient of static friction between the block and the floor puts the block on the verge of sliding?

A block of mass 2kg is kept on the floor. The coefficient of static friction is 0.4 . If a force F of 2.5N is applied on the block as shown in the figure, the frictional force between the block and the floor will be.

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 3 N is applied on the block as shown in figure. The force of friction between the block and the floor is (Take g=10 m s^(-2) )

In Fig. 6-48, a 2.0 kg block lies on a 20 kg trolley that can roll across a floor on frictionless bearings. Between the block and the trolley, the coefficient of kinetic friction is 0.20 and the coefficient of static friction is 0.25. When a horizontal 2.0 N force is applied to the block, what are the magnitudes of (a) the frictional force between the block and the trolley and (b) the acceleration of the trolley?

A block of mass 4 kg is kept on a rough horizontal surface. The coefficient of static friction is 0.8. If a force of 19 N is applied on the block parallel to the floor, then the force of friction between the block and floor is

In Fig. 6-37, a block of mass m = 5.0 kg is at rest on a ramp. The coefficient of static friction between the block and ramp is not known. Find the magnitude of the net force exerted by the ramp on the block.

A block of mass 2 kg is at rest on a floor . The coefficient of static friction between block and the floor is 0.54. A horizonatl force of 2.8 N is applied to the block . What should be the frictional force between the block and the floor ? ( take , g = 10 m//s^(2) )

A block of mass 2 kg is placed on the floor . The coefficient of static friction is 0.4 . If a force of 2.8 N is applied on the block parallel to floor , the force of friction between the block and floor is : (Taking g = 10 m//s^(2) )

A block of mass M is sliding down the plane. Coefficient of static friction is mu_(s) and kinetic friction is mu_(k) . Then friction force acting on the block is :